php - Retrieve data from a certain column and i can change the image whenever the data is different -


is possible retrieve data column , have if else statement can change image? want pic tally location retrieve database.

<?php  $servername = "......byethost5.com"; $username = "...."; $password = "..."; $dbname = "b...";  // create connection $conn = new mysqli($servername, $username, $password, $dbname); // check connection if ($conn->connect_error) {     die("connection failed: " . $conn->connect_error); }  $sql = "select location,datetime sensordetails limit 1"; $result = $conn->query($sql);  if ($result->num_rows > 0) {     // output data of each row     while($row = $result->fetch_assoc()) {         echo "last seen location: " . $row["location"]."<br>";                  $help= $row["location"];             if($help=='toilet')              {echo '<center><img src="toilet.jpg"></center>';}             elseif($help=='kitchen')               {echo '<center><img src="kitchen.jpg</center>';}             else {echo '<center><img src="bedroom.jpg"></center>';}       } } else {     echo "0 results"; }  $conn->close(); ?>

another solution use same name 'location' field , current image.

<?php         $servername = "......byethost5.com";     $username = "....";     $password = "...";     $dbname = "b...";       //////////////////////////////////////////////////////     //image folder     //put here folder save images     $img_folder = './'; //current folder     /////////////////////////////////////////////////////      // create connection     $conn = new mysqli($servername, $username, $password, $dbname);     // check connection     if ($conn->connect_error) {     die("connection failed: " . $conn->connect_error);     }      $sql = "select location,datetime sensordetails limit 1";     $result = $conn->query($sql);      if ($result->num_rows > 0) {     // output data of each row         while($row = $result->fetch_assoc()) {              $img_file = $img_folder . $row["location"] . '.jpg';               //echo $img_file; //uncomment if wanna check img's path.             if( ! file_exists($img_file) ){//check if file exists                 $img_file = '';                      }                                    echo "last seen location: " . $row["location"]."<br>";         echo "<center><img src="$img_file"></center>";       }                           }else {     echo "<p> 0 results </p>";     }      $conn->close(); ?>

this solution more appropriate if you're going have more locations in future. supposed keep images in same folder script , images in jpg format.


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