python - inplace removal of quotes from list of list -


i changed list 

orig_list=['"jason","hello1,hello2,hello3","somegroup2","bundle1","loc1"', '"ruby","hello","somegroup","bundle2","loc2"', '"sam","hello3,hello2","somegroup3,somegroup4","bundle2","loc3"']  new_list=[x.split(",") x in orig_list]   new_list=[['"jason"', '"hello1', 'hello2', 'hello3"', '"somegroup2"', '"bundle1"', '"loc1"'], ['"ruby"', '"hello"', '"somegroup"', '"bundle2"', '"loc2"'], ['"sam"', '"hello3', 'hello2"', '"somegroup3', 'somegroup4"', '"bundle2"', '"loc3"']]

what intent 

[['jason', 'hello1,hello2,hello3', 'somegroup2', 'bundle1', 'loc1'], ['ruby', 'hello', 'somegroup', 'bundle2', 'loc2'], ['sam', 'hello3,hello2', 'somegroup3,somegroup4', 'bundle2', 'loc3']]

is possible inplace , not creating new one?

update : can have elements in double quotes, in double quotes, no double quotes , same in single quotes.

if need in-place removal of quotes, need add in [:] list comprehension assignment:

orig_list = ['"jason","hello1,hello2,hello3","somegroup2","bundle1","loc1"', '"ruby","hello","somegroup","bundle2","loc2"', '"sam","hello3,hello2","somegroup3,somegroup4","bundle2","loc3"'] id1 = id(orig_list)  orig_list[:] = [w w in orig_list] orig_list[:] = [g.replace('"', "'") g in orig_list] orig_list[:] = [h.split("',") h in orig_list] orig_list[:] = [[j.replace("'", '') j in k] k in orig_list]  id2 = id(orig_list) print id1 == id2  # true print orig_list  # [['jason', 'hello1,hello2,hello3', 'somegroup2', 'bundle1', 'loc1'], ['ruby', 'hello', 'somegroup', 'bundle2', 'loc2'], ['sam', 'hello3,hello2', 'somegroup3,somegroup4', 'bundle2', 'loc3']]

note orig_list[:] = .... ensures don't create copy of list (hence, making not in-place).


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