xml - How can I write a namespace agnostic XPath query using XPath axes -


let's have xml presented below:

<ns1:test xmlns:ns1="http://www.w3.org/tr/html3/"  xmlns:uml="http://www.w3.org/tr/html4/">     <uml:class name="test1">         <uml:modelelement.stereotype>             <uml:stereotype name="afv"/>         </uml:modelelement.stereotype>     </uml:class>     <uml:class name="test2" >         <uml:modelelement.stereotype>             <uml:stereotype name="afv"/>         </uml:modelelement.stereotype>     </uml:class>     <uml:class name="test3" >         <uml:modelelement.stereotype>             <uml:stereotype name="rcs"/>         </uml:modelelement.stereotype>     </uml:class>     <uml:class name="test4" >         <uml:modelelement.stereotype>             <uml:stereotype name="dfk"/>         </uml:modelelement.stereotype>     </uml:class>     <uml:class name="test5" >         <uml:modelelement.stereotype>             <uml:stereotype name="dso"/>         </uml:modelelement.stereotype>     </uml:class> </ns1:test>

how can write namespace agnostic xpath query "class" elements containing "stereotype" element attribute name equal "afv" ?

if there weren't namespaces, have use called xpath axes, , query have looked : //class[descendant::stereotype[@name='afv']]

the xpath query should return:

<uml:class name="test1">         <uml:modelelement.stereotype>             <uml:stereotype name="afv"/>         </uml:modelelement.stereotype>     </uml:class>     <uml:class name="test2" >         <uml:modelelement.stereotype>             <uml:stereotype name="afv"/>         </uml:modelelement.stereotype>     </uml:class>

you can use xpath local-name() function match element's local name ignoring namespaces :

//*[local-name()='class'][descendant::*[local-name()='stereotype' , @name='afv']]

-

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