c - Why is my password checking code not working correctly? It gives same output regardless of whatsoever input -

i made password checking program checks following criteria:-

• should have atleast

  • 1 uppercase
  • 1 lower case
  • 1 special character
  • 1 number
• should lesser 100 characters

and thats it. have not given lower limit. , no matter input give (correct or incorrect), program gives me same or similar output attached in screenshot.

for eg:- pratik10, pratik10, pratikten, pr@tik10, same output "password fine , valid".

why program not checking defined conditions correctly? not printing counters of password correctly.

following code:

#include <stdio.h> #include <conio.h> #include <stdlib.h> #include <ctype.h> #include <math.h> #include <string.h>  int main() {     char x[100];     int i;     int uc=0;     int lc=0;     int num=0;     int misc=0;      printf("enter password\n");     scanf("%s",x);      for(i=0;i<100;i++) {         if (isalpha(x[i])) {             if (isupper(x[i])) {                 uc++;             }             if (islower(x[i])) {                 lc++;             }         }         if (isdigit(x[i])) {             num++;         }         else {               misc++;         }     }      printf("checking password\n");     printf("%d uc\n",uc);     printf("%d lc\n",lc);     printf("%d num\n",num);     printf("%d misc\n",misc);      if ((uc > 0) && (lc > 0) && (num > 0) && (misc > 0)) {         printf("password fine , valid\n");     }     else {         if(lc<=0) {             printf("lowercase character(s) missing cannot proceed without inclusion\n");         }         if(uc<=0) {             printf("uppercase character(s) missing cannot proceed without inclusion\n");         }         if(num<=0) {             printf("number(s) missing cannot proceed without inclusion\n");         }         if(misc<=0) {             printf("special character(s) missing cannot proceed without inclusion\n");         }         printf("please include missing parameters in combination validate password , try again\n\n");     }      return 0; } 

how correct this?

output:

you should check null-terminated string provided input user.

in other words, should iterate x until encounter null-character.

---

change this:

for (i = 0; < 100; i++) 

to this:

for (i = 0; x[i] != 0; i++) 

---

a second problem not using if/else properly.

as result, every character not digit counted misc.

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change this:

if (isdigit(x[i])) 

to this:

else if (isdigit(x[i]))