c - looking for numbers in a character array -

i'm writing program reads lines file need print out numbers, lines read stored in character array:

char line[255]; //code read line file here (c=0;c<256;c++) {   if (line[c]<58 && line[c]>47)     printf("the character is: %c\n",line[c]); } 

the configuration file has following lines:

buttons 3

the result i'd the character 3, instead 3,9,4,4

hope i've provided sufficient information. thanks

your if-statement wrong.

you can express clearer, , more correctly as:

if ('0' <= line[c] && line[c] <= '9') {     printf("the character is: %c\n",line[c]); } 

---

your loop runs 256 characters, though input of "buttons" has 7 characters. you're running off memory not yours, , finding 9, 4, 4, there random chance.

you want:

for (int c=0; c < 256; ++c) {     if (line[c] == '\0')    // if end of input found, stop loop.     {         break;     }     if ('0' <= line[c] && line[c] <= '9')     {         printf("the character is: %c\n",line[c]);     } }