php - Bash seems to be executing command 2nd time when variable of captured output is used - 


output=$(php -f somecommand arg1 arg2 arg3 2>&1) echo "$output" >> error.log

the script runs cron. in emailed output received looks php -f ... command run twice.

is run once when variable set, , again when variable echoed? don't remember behavior happening before.

if happening... how program output variable without re-executing program?


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