How to avoid hard coding in if condition of python script -

i new python. have query regarding un-hardcoding object names(if condition) in python script. have fruit = [ apple, mango, pineapple, banana, oranges] , size = [ small, medium , big] write code below:

if (fruit == apple, size == small):     statement 1    statement 2 elif (fruit == apple, size == medium):    statement 1    statement 2 elif (fruit == apple, size == big):    statement 1    statement 2 elif (fruit == mango, size == small):    statement 1    statement 2 elif (fruit == mango, size = medium):    statement 1    statement 2 

how can avoid writing multiple if...else conditions?

statement 1: pulling dot file related fruit , size directory path structure main-directory/fruit/collateral/fruit_size.dot statement 2: pulling txt file related fruit , size directory path structure main-directory/source/readparamters/readparam/fruit_size.txt

i want execute statements each condition 1 @ time. take inputs fruit , size user. there way in python script can automatically take combinations 1 one , execute statements? know it's complex , python expert can me.

how using itertools.product , handling errors try..catch. https://docs.python.org/3/library/itertools.html#itertools.product

import itertools  fruits = ['apple', 'mango', 'pineapple', 'banana', 'oranges'] sizes = ['small', 'medium', 'big']  fruit, size in itertools.product(fruits, sizes):     dot_file = 'main-directory/{fruit}/collateral/{fruit}_{size}.dot'.format(fruit=fruit, size=size)     text_file = 'main-directory/source/readparamters/readparam/{fruit}_{size}.txt'.format(fruit=fruit, size=size)     try:         open(dot_file)  # statement 1         open(text_file)  # statement 2     except exception e:         print(e)  # handle erorrs! 

or, check file existence os.path.isfile without using try..catch.

import os ..     dot_file = ..     text_file = ..     if os.path.isfile(dot_file):         open(dot_file)  # statement 1     if os.path.isfile(text_file):         open(text_file)  # statement 2 

itertools.product generates cartesian product of input iterables.

>>> fruits = ['apple', 'mango', 'pineapple', 'banana', 'oranges'] >>> sizes = ['small', 'medium', 'big'] >>> list(itertools.product(fruits, sizes)) [('apple', 'small'), ('apple', 'medium'), ('apple', 'big'), ('mango', 'small'), ('mango', 'medium'), ('mango', 'big'), ('pineapple', 'small'), ('pineapple', 'medium'), ('pineapple', 'big'), ('banana', 'small'), ('banana', 'medium'), ('banana', 'big'), ('oranges', 'small'), ('oranges', 'medium'), ('oranges', 'big')]